69. Sqrt(x)
Difficulty: Easy
Topics: Math, Binary Search
Similar Questions:
Problem:
Implement int sqrt(int x)
.
Compute and return the square root of x, where x is guaranteed to be a non-negative integer.
Since the return type is an integer, the decimal digits are truncated and only the integer part of the result is returned.
Example 1:
Input: 4 Output: 2
Example 2:
Input: 8 Output: 2 Explanation: The square root of 8 is 2.82842..., and since the decimal part is truncated, 2 is returned.
Solutions:
class Solution {
public:
int mySqrt(int x) {
int left = 0;
int right = INT_MAX;
while (left + 1 < right) {
int mid = left + (right - left)/2;
if (x/mid >= mid) { // mid * mid <= x would cause overflow
left = mid;
} else {
right = mid;
}
}
if (x/right >= right) return right;
return left;
}
};