270. Closest Binary Search Tree Value
Difficulty: Easy
Topics: Binary Search, Tree
Similar Questions:
Problem:
Given a non-empty binary search tree and a target value, find the value in the BST that is closest to the target.
Note:
- Given target value is a floating point.
- You are guaranteed to have only one unique value in the BST that is closest to the target.
Example:
Input: root = [4,2,5,1,3], target = 3.714286 4 / \ 2 5 / \ 1 3 Output: 4
Solutions:
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
int closestValue(TreeNode* root, double target) {
int ret = root->val;
if (root->left) {
int leftClose = closestValue(root->left, target);
if (abs(ret - target) > abs(leftClose - target)) {
ret = leftClose;
}
}
if (root->right) {
int rightClose = closestValue(root->right, target);
if (abs(ret - target) > abs(rightClose - target)) {
ret = rightClose;
}
}
return ret;
}
};