507. Perfect Number
Difficulty: Easy
Topics: Math
Similar Questions:
Problem:
We define the Perfect Number is a positive integer that is equal to the sum of all its positive divisors except itself.
Now, given an integer n, write a function that returns true when it is a perfect number and false when it is not.Example:
Input: 28 Output: True Explanation: 28 = 1 + 2 + 4 + 7 + 14
Note: The input number n will not exceed 100,000,000. (1e8)
Solutions:
class Solution {
public:
bool checkPerfectNumber(int num) {
if (num <= 1) return false;
int sum = 1;
int root = sqrt(num);
for (int i = 2; i <= root; ++i) {
if (num % i == 0) {
sum += i + num / i;
}
}
if (root * root == num) {
sum -= root;
}
return sum == num;
}
};