598. Range Addition II
Difficulty: Easy
Topics: Math
Similar Questions:
Problem:
Given an m * n matrix M initialized with all 0's and several update operations.
Operations are represented by a 2D array, and each operation is represented by an array with two positive integers a and b, which means M[i][j] should be added by one for all 0 <= i="" <="" a<="" b=""> and 0 <= j="" <="" b<="" b="">. =>=>
You need to count and return the number of maximum integers in the matrix after performing all the operations.
Example 1:
Input: m = 3, n = 3 operations = [[2,2],[3,3]] Output: 4 Explanation: Initially, M = [[0, 0, 0], [0, 0, 0], [0, 0, 0]] After performing [2,2], M = [[1, 1, 0], [1, 1, 0], [0, 0, 0]] After performing [3,3], M = [[2, 2, 1], [2, 2, 1], [1, 1, 1]] So the maximum integer in M is 2, and there are four of it in M. So return 4.
Note:
Solutions:
class Solution {
public:
int maxCount(int m, int n, vector<vector<int>>& ops) {
int row = m;
int col = n;
for (auto& op : ops) {
row = min(row, op[0]);
col = min(col, op[1]);
}
return (row) * (col);
}
};