598. Range Addition II

Problem:

Given an m * n matrix M initialized with all 0's and several update operations.

Operations are represented by a 2D array, and each operation is represented by an array with two positive integers a and b, which means M[i][j] should be added by one for all 0 <= i="" <="" a<="" b=""> and 0 <= j="" <="" b<="" b="">.

You need to count and return the number of maximum integers in the matrix after performing all the operations.

Example 1:

Input: 
m = 3, n = 3
operations = [[2,2],[3,3]]
Output: 4
Explanation: 
Initially, M = 
[[0, 0, 0],
 [0, 0, 0],
 [0, 0, 0]]

After performing [2,2], M = 
[[1, 1, 0],
 [1, 1, 0],
 [0, 0, 0]]

After performing [3,3], M = 
[[2, 2, 1],
 [2, 2, 1],
 [1, 1, 1]]

So the maximum integer in M is 2, and there are four of it in M. So return 4.

Note:

  1. The range of m and n is [1,40000].
  2. The range of a is [1,m], and the range of b is [1,n].
  3. The range of operations size won't exceed 10,000.
  4. </ol> </p>

    Solutions:

    class Solution {
    public:
        int maxCount(int m, int n, vector<vector<int>>& ops) {
            int row = m;
            int col = n;
    
            for (auto& op : ops) {
                row = min(row, op[0]);
                col = min(col, op[1]);
            }
    
            return (row) * (col);
        }
    };
    

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