350. Intersection of Two Arrays II
Difficulty: Easy
Topics: Hash Table, Two Pointers, Binary Search, Sort
Similar Questions:
Problem:
Given two arrays, write a function to compute their intersection.
Example 1:
Input: nums1 = [1,2,2,1], nums2 = [2,2] Output: [2,2]
Example 2:
Input: nums1 = [4,9,5], nums2 = [9,4,9,8,4] Output: [4,9]
Note:
- Each element in the result should appear as many times as it shows in both arrays.
- The result can be in any order.
Follow up:
- What if the given array is already sorted? How would you optimize your algorithm?
- What if nums1's size is small compared to nums2's size? Which algorithm is better?
- What if elements of nums2 are stored on disk, and the memory is limited such that you cannot load all elements into the memory at once?
Solutions:
class Solution {
public:
vector<int> intersect(vector<int>& nums1, vector<int>& nums2) {
if (nums1.size() > nums2.size()) {
return intersect(nums2, nums1);
}
unordered_multiset<int> numSet(nums1.begin(), nums1.end());
vector<int> ret;
for (auto num : nums2) {
auto it = numSet.find(num);
if (it != numSet.end()) {
ret.push_back(num);
numSet.erase(it);
}
}
return ret;
}
};