144. Binary Tree Preorder Traversal
Difficulty: Medium
Topics: Stack, Tree
Similar Questions:
Problem:
Given a binary tree, return the preorder traversal of its nodes' values.
Example:
Input:[1,null,2,3]
1 \ 2 / 3 Output:[1,2,3]
Follow up: Recursive solution is trivial, could you do it iteratively?
Solutions:
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
vector<int> preorderTraversal(TreeNode* root) {
vector<int> ret;
TreeNode* cur = root;
while (cur) {
TreeNode* pre = cur->left;
if (pre == nullptr) {
ret.push_back(cur->val); // visit
cur = cur->right;
continue;
}
while (pre->right != nullptr && pre->right != cur) {
pre = pre->right;
}
if (pre->right == nullptr) {
pre->right = cur;
ret.push_back(cur->val); // visit
cur = cur->left;
} else {
pre->right = nullptr;
cur = cur->right;
}
}
return ret;
}
};