717. 1-bit and 2-bit Characters

  • Difficulty: Easy

  • Topics: Array

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Problem:

We have two special characters. The first character can be represented by one bit 0. The second character can be represented by two bits (10 or 11).

Now given a string represented by several bits. Return whether the last character must be a one-bit character or not. The given string will always end with a zero.

Example 1:

Input: 
bits = [1, 0, 0]
Output: True
Explanation: 
The only way to decode it is two-bit character and one-bit character. So the last character is one-bit character.

Example 2:

Input: 
bits = [1, 1, 1, 0]
Output: False
Explanation: 
The only way to decode it is two-bit character and two-bit character. So the last character is NOT one-bit character.

Note:

  • 1 .
  • bits[i] is always 0 or 1.
  • </p>

    Solutions:

    class Solution {
    public:
        bool isOneBitCharacter(vector<int>& bits) {
            bool oneBit;
            for (int i = 0; i < bits.size();) {
                if (bits[i] == 0) {
                    oneBit = true;
                    ++i;
                } else {
                    oneBit = false;
                    i += 2;
                }
            }
    
            return oneBit;
        }
    };
    

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