73. Set Matrix Zeroes
Difficulty: Medium
Topics: Array
Similar Questions:
Problem:
Given a m x n matrix, if an element is 0, set its entire row and column to 0. Do it in-place.
Example 1:
Input: [ [1,1,1], [1,0,1], [1,1,1] ] Output: [ [1,0,1], [0,0,0], [1,0,1] ]
Example 2:
Input: [ [0,1,2,0], [3,4,5,2], [1,3,1,5] ] Output: [ [0,0,0,0], [0,4,5,0], [0,3,1,0] ]
Follow up:
- A straight forward solution using O(mn) space is probably a bad idea.
- A simple improvement uses O(m + n) space, but still not the best solution.
- Could you devise a constant space solution?
Solutions:
class Solution {
public:
void setZeroes(vector<vector<int>>& matrix) {
int m = matrix.size();
if (m == 0) return;
int n = matrix[0].size();
if (n == 0) return;
bool firstRowSet = false;
bool firstColSet = false;
for (int i = 0; i < m; ++i) {
for (int j = 0; j < n; ++j) {
if (matrix[i][j] == 0) {
if (i == 0 && j == 0) {
firstRowSet = true;
firstColSet = true;
} else if (i == 0) {
firstRowSet = true;
matrix[0][j] = 0;
} else if (j == 0) {
firstColSet = true;
matrix[i][0] = 0;
} else {
matrix[i][0] = 0;
matrix[0][j] = 0;
}
}
}
}
for (int i = 1; i < m; ++i) {
if (matrix[i][0] == 0) {
for (int j = 1; j < n; ++j) {
matrix[i][j] = 0;
}
}
}
for (int j = 1; j < n; ++j) {
if (matrix[0][j] == 0) {
for (int i = 1; i < m; ++i) {
matrix[i][j] = 0;
}
}
}
if (firstRowSet) {
for (int j = 0; j < n; ++j) {
matrix[0][j] = 0;
}
}
if (firstColSet) {
for (int i = 0; i < m; ++i) {
matrix[i][0] = 0;
}
}
}
};