745. Find Smallest Letter Greater Than Target
Difficulty: Easy
Topics: Binary Search
Similar Questions:
Problem:
Given a list of sorted characters letters
containing only lowercase letters, and given a target letter target
, find the smallest element in the list that is larger than the given target.
Letters also wrap around. For example, if the target is target = 'z'
and letters = ['a', 'b']
, the answer is 'a'
.
Examples:
Input: letters = ["c", "f", "j"] target = "a" Output: "c" Input: letters = ["c", "f", "j"] target = "c" Output: "f" Input: letters = ["c", "f", "j"] target = "d" Output: "f" Input: letters = ["c", "f", "j"] target = "g" Output: "j" Input: letters = ["c", "f", "j"] target = "j" Output: "c" Input: letters = ["c", "f", "j"] target = "k" Output: "c"
Note:
letters
has a length in range [2, 10000]
.letters
consists of lowercase letters, and contains at least 2 unique letters.target
is a lowercase letter.Solutions:
class Solution {
public:
char nextGreatestLetter(vector<char>& letters, char target) {
auto it = upper_bound(letters.begin(), letters.end(), target);
return it == letters.end() ? letters[0] : *it;
}
};