153. Find Minimum in Rotated Sorted Array
Difficulty: Medium
Topics: Array, Binary Search
Similar Questions:
Problem:
Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand.
(i.e., [0,1,2,4,5,6,7]
might become [4,5,6,7,0,1,2]
).
Find the minimum element.
You may assume no duplicate exists in the array.
Example 1:
Input: [3,4,5,1,2] Output: 1
Example 2:
Input: [4,5,6,7,0,1,2] Output: 0
Solutions:
class Solution {
public:
typedef bool (*check)(vector<int>&, int index);
static bool checkMin(vector<int>& nums, int index) {
return nums[index] < nums[0];
}
int findMin(vector<int>& nums) {
if (nums.size() == 0) return -1;
if (nums.size() == 1) return nums[0];
if (nums[0] < nums.back()) return nums[0];
int left = 0;
int right = nums.size() - 1;
while (left < right) {
int mid = left + (right - left)/2;
if (checkMin(nums, mid)) {
right = mid;
} else {
left = mid + 1;
}
}
return nums[left];
}
};