1033. Broken Calculator
Difficulty: Medium
Topics: Math, Greedy
Similar Questions:
Problem:
On a broken calculator that has a number showing on its display, we can perform two operations:
- Double: Multiply the number on the display by 2, or;
- Decrement: Subtract 1 from the number on the display.
Initially, the calculator is displaying the number X
.
Return the minimum number of operations needed to display the number Y
.
Example 1:
Input: X = 2, Y = 3 Output: 2 Explanation: Use double operation and then decrement operation {2 -> 4 -> 3}.
Example 2:
Input: X = 5, Y = 8 Output: 2 Explanation: Use decrement and then double {5 -> 4 -> 8}.
Example 3:
Input: X = 3, Y = 10 Output: 3 Explanation: Use double, decrement and double {3 -> 6 -> 5 -> 10}.
Example 4:
Input: X = 1024, Y = 1 Output: 1023 Explanation: Use decrement operations 1023 times.
Note:
1 <= X <= 10^9
1 <= Y <= 10^9
Solutions:
class Solution {
public:
int brokenCalc(int X, int Y) {
int ret = 0;
while (Y > X) {
if (Y % 2 == 0) {
Y /= 2;
++ret;
} else {
++Y;
Y /= 2;
ret += 2;
}
}
ret += (X - Y);
return ret;
}
};