398. Random Pick Index

Problem:

Given an array of integers with possible duplicates, randomly output the index of a given target number. You can assume that the given target number must exist in the array.

Note:
The array size can be very large. Solution that uses too much extra space will not pass the judge.

Example:

int[] nums = new int[] {1,2,3,3,3};
Solution solution = new Solution(nums);

// pick(3) should return either index 2, 3, or 4 randomly. Each index should have equal probability of returning.
solution.pick(3);

// pick(1) should return 0. Since in the array only nums[0] is equal to 1.
solution.pick(1);

Solutions:

class Solution {
public:
    Solution(vector<int>& nums) {
        this->nums = nums;
    }

    int pick(int target) {
        int count = 0;
        int ret;
        for (int i = 0; i < nums.size(); ++i) {
            if (nums[i] != target)  continue;
            ++count;
            if (rand() % count == 0) {
                ret = i;
            }
        }

        return ret;
    }

private:
    vector<int> nums;

};

/**
 * Your Solution object will be instantiated and called as such:
 * Solution* obj = new Solution(nums);
 * int param_1 = obj->pick(target);
 */

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