782. Jewels and Stones

  • Difficulty: Easy

  • Topics: Hash Table

  • Similar Questions:

Problem:

You're given strings J representing the types of stones that are jewels, and S representing the stones you have.  Each character in S is a type of stone you have.  You want to know how many of the stones you have are also jewels.

The letters in J are guaranteed distinct, and all characters in J and S are letters. Letters are case sensitive, so "a" is considered a different type of stone from "A".

Example 1:

Input: J = "aA", S = "aAAbbbb"
Output: 3

Example 2:

Input: J = "z", S = "ZZ"
Output: 0

Note:

  • S and J will consist of letters and have length at most 50.
  • The characters in J are distinct.

Solutions:

class Solution {
public:
    int numJewelsInStones(string J, string S) {
        unordered_set<char> jeweries (J.begin(), J.end());
        int count = 0;
        for (auto& stone : S) {
            if (jeweries.count(stone) > 0) {
                ++count; 
            }
        }

        return count;
    }
};

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