1033. Broken Calculator

  • Difficulty: Medium

  • Topics: Math, Greedy

  • Similar Questions:

Problem:

On a broken calculator that has a number showing on its display, we can perform two operations:

  • Double: Multiply the number on the display by 2, or;
  • Decrement: Subtract 1 from the number on the display.

Initially, the calculator is displaying the number X.

Return the minimum number of operations needed to display the number Y.

 

Example 1:

Input: X = 2, Y = 3
Output: 2
Explanation: Use double operation and then decrement operation {2 -> 4 -> 3}.

Example 2:

Input: X = 5, Y = 8
Output: 2
Explanation: Use decrement and then double {5 -> 4 -> 8}.

Example 3:

Input: X = 3, Y = 10
Output: 3
Explanation:  Use double, decrement and double {3 -> 6 -> 5 -> 10}.

Example 4:

Input: X = 1024, Y = 1
Output: 1023
Explanation: Use decrement operations 1023 times.

 

Note:

  1. 1 <= X <= 10^9
  2. 1 <= Y <= 10^9

Solutions:

class Solution {
public:
    int brokenCalc(int X, int Y) {
        int ret = 0;
        while (Y > X) {
            if (Y % 2 == 0) {
                Y /= 2;
                ++ret;
            } else {
                ++Y;
                Y /= 2;
                ret += 2;
            }
        }

        ret += (X - Y);

        return ret;

    }
};

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